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4x(6x-26)=360
We move all terms to the left:
4x(6x-26)-(360)=0
We multiply parentheses
24x^2-104x-360=0
a = 24; b = -104; c = -360;
Δ = b2-4ac
Δ = -1042-4·24·(-360)
Δ = 45376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{45376}=\sqrt{64*709}=\sqrt{64}*\sqrt{709}=8\sqrt{709}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-8\sqrt{709}}{2*24}=\frac{104-8\sqrt{709}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+8\sqrt{709}}{2*24}=\frac{104+8\sqrt{709}}{48} $
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