4x(6-5x)/3=0

Solution for 4x(6-5x)/3=0 equation:

4x(6-5x)/3=0

We add all the numbers together, and all the variables

4x(-5x+6)/3=0

We multiply all the terms by the denominator


4x(-5x+6)=0

We multiply parentheses

-20x^2+24x=0

a = -20; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-20)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-20}=\frac{-48}{-40}
=1+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-20}=\frac{0}{-40}
=0
$