4x(2x-3)=4x(2x-1)

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Solution for 4x(2x-3)=4x(2x-1) equation: 



4x(2x-3)=4x(2x-1)

We move all terms to the left:

4x(2x-3)-(4x(2x-1))=0

We multiply parentheses

8x^2-12x-(4x(2x-1))=0



We calculate terms in parentheses: -(4x(2x-1)), so:

4x(2x-1)

We multiply parentheses

8x^2-4x

Back to the equation:

-(8x^2-4x)



We get rid of parentheses

8x^2-8x^2-12x+4x=0

We add all the numbers together, and all the variables

-8x=0

x=0/-8

x=0

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