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4x(2x+3)=6x+2
We move all terms to the left:
4x(2x+3)-(6x+2)=0
We multiply parentheses
8x^2+12x-(6x+2)=0
We get rid of parentheses
8x^2+12x-6x-2=0
We add all the numbers together, and all the variables
8x^2+6x-2=0
a = 8; b = 6; c = -2;
Δ = b2-4ac
Δ = 62-4·8·(-2)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-10}{2*8}=\frac{-16}{16} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+10}{2*8}=\frac{4}{16} =1/4 $
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