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4x(2+1x)=25(5x+5)
We move all terms to the left:
4x(2+1x)-(25(5x+5))=0
We add all the numbers together, and all the variables
4x(x+2)-(25(5x+5))=0
We multiply parentheses
4x^2+8x-(25(5x+5))=0
We calculate terms in parentheses: -(25(5x+5)), so:We get rid of parentheses
25(5x+5)
We multiply parentheses
125x+125
Back to the equation:
-(125x+125)
4x^2+8x-125x-125=0
We add all the numbers together, and all the variables
4x^2-117x-125=0
a = 4; b = -117; c = -125;
Δ = b2-4ac
Δ = -1172-4·4·(-125)
Δ = 15689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-117)-\sqrt{15689}}{2*4}=\frac{117-\sqrt{15689}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-117)+\sqrt{15689}}{2*4}=\frac{117+\sqrt{15689}}{8} $
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