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4x(2)=2x+10(2)
We move all terms to the left:
4x(2)-(2x+10(2))=0
We add all the numbers together, and all the variables
4x^2-(2x+102)=0
We get rid of parentheses
4x^2-2x-102=0
a = 4; b = -2; c = -102;
Δ = b2-4ac
Δ = -22-4·4·(-102)
Δ = 1636
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1636}=\sqrt{4*409}=\sqrt{4}*\sqrt{409}=2\sqrt{409}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{409}}{2*4}=\frac{2-2\sqrt{409}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{409}}{2*4}=\frac{2+2\sqrt{409}}{8} $
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