4x(2)+4x-35=0

Solution for 4x(2)+4x-35=0 equation:

4x(2)+4x-35=0

We add all the numbers together, and all the variables

4x^2+4x-35=0

a = 4; b = 4; c = -35;
Δ = b2-4ac
Δ = 42-4·4·(-35)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-24}{2*4}=\frac{-28}{8}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+24}{2*4}=\frac{20}{8}
=2+1/2
$