4x(14+3x)=161

Solution for 4x(14+3x)=161 equation:

4x(14+3x)=161

We move all terms to the left:

4x(14+3x)-(161)=0

We add all the numbers together, and all the variables

4x(3x+14)-161=0

We multiply parentheses

12x^2+56x-161=0

a = 12; b = 56; c = -161;
Δ = b2-4ac
Δ = 562-4·12·(-161)
Δ = 10864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10864}=\sqrt{16*679}=\sqrt{16}*\sqrt{679}=4\sqrt{679}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-4\sqrt{679}}{2*12}=\frac{-56-4\sqrt{679}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+4\sqrt{679}}{2*12}=\frac{-56+4\sqrt{679}}{24}
$