4x(12-10x)=8(4x+1)

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Solution for 4x(12-10x)=8(4x+1) equation: 



4x(12-10x)=8(4x+1)

We move all terms to the left:

4x(12-10x)-(8(4x+1))=0

We add all the numbers together, and all the variables

4x(-10x+12)-(8(4x+1))=0

We multiply parentheses

-40x^2+48x-(8(4x+1))=0



We calculate terms in parentheses: -(8(4x+1)), so:

8(4x+1)

We multiply parentheses

32x+8

Back to the equation:

-(32x+8)



We get rid of parentheses

-40x^2+48x-32x-8=0

We add all the numbers together, and all the variables

-40x^2+16x-8=0

a = -40; b = 16; c = -8;
Δ = b2-4ac
Δ = 162-4·(-40)·(-8)
Δ = -1024
Delta is less than zero, so there is no solution for the equation

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