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4x(-4x-14)=14
We move all terms to the left:
4x(-4x-14)-(14)=0
We multiply parentheses
-16x^2-56x-14=0
a = -16; b = -56; c = -14;
Δ = b2-4ac
Δ = -562-4·(-16)·(-14)
Δ = 2240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2240}=\sqrt{64*35}=\sqrt{64}*\sqrt{35}=8\sqrt{35}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-8\sqrt{35}}{2*-16}=\frac{56-8\sqrt{35}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+8\sqrt{35}}{2*-16}=\frac{56+8\sqrt{35}}{-32} $
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