4x^2+100x+25=0

Solution for 4x^2+100x+25=0 equation:

4x^2+100x+25=0

a = 4; b = 100; c = +25;
Δ = b2-4ac
Δ = 1002-4·4·25
Δ = 9600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9600}=\sqrt{1600*6}=\sqrt{1600}*\sqrt{6}=40\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-40\sqrt{6}}{2*4}=\frac{-100-40\sqrt{6}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+40\sqrt{6}}{2*4}=\frac{-100+40\sqrt{6}}{8}
$