4v/2=4(v+4)/3

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Solution for 4v/2=4(v+4)/3 equation: 



4v/2=4(v+4)/3

We move all terms to the left:

4v/2-(4(v+4)/3)=0

We calculate fractions


12v^2/()+(-(4(v+4)*2)/()=0



We calculate terms in parentheses: +(-(4(v+4)*2)/(), so:

-(4(v+4)*2)/(

We multiply all the terms by the denominator


-(4(v+4)*2)



We calculate terms in parentheses: -(4(v+4)*2), so:

4(v+4)*2

We multiply parentheses

8v+32

Back to the equation:

-(8v+32)



We get rid of parentheses

-8v-32

Back to the equation:

+(-8v-32)



We get rid of parentheses

12v^2/()-8v-32=0

We multiply all the terms by the denominator


12v^2-8v*()-32*()=0

We add all the numbers together, and all the variables

12v^2-8v*()=0

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