4v-8+2(3v+1)=-4(v+1)

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Solution for 4v-8+2(3v+1)=-4(v+1) equation: 



4v-8+2(3v+1)=-4(v+1)

We move all terms to the left:

4v-8+2(3v+1)-(-4(v+1))=0

We multiply parentheses

4v+6v-(-4(v+1))+2-8=0



We calculate terms in parentheses: -(-4(v+1)), so:

-4(v+1)

We multiply parentheses

-4v-4

Back to the equation:

-(-4v-4)



We add all the numbers together, and all the variables

10v-(-4v-4)-6=0

We get rid of parentheses

10v+4v+4-6=0

We add all the numbers together, and all the variables

14v-2=0

We move all terms containing v to the left, all other terms to the right

14v=2

v=2/14

v=1/7

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