4v-4+4(3v+1)=-2(v+2)

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Solution for 4v-4+4(3v+1)=-2(v+2) equation: 



4v-4+4(3v+1)=-2(v+2)

We move all terms to the left:

4v-4+4(3v+1)-(-2(v+2))=0

We multiply parentheses

4v+12v-(-2(v+2))+4-4=0



We calculate terms in parentheses: -(-2(v+2)), so:

-2(v+2)

We multiply parentheses

-2v-4

Back to the equation:

-(-2v-4)



We add all the numbers together, and all the variables

16v-(-2v-4)=0

We get rid of parentheses

16v+2v+4=0

We add all the numbers together, and all the variables

18v+4=0

We move all terms containing v to the left, all other terms to the right

18v=-4

v=-4/18

v=-2/9

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