4u-2+41(2u+1)=-3(u+1)

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Solution for 4u-2+41(2u+1)=-3(u+1) equation:



4u-2+41(2u+1)=-3(u+1)
We move all terms to the left:
4u-2+41(2u+1)-(-3(u+1))=0
We multiply parentheses
4u+82u-(-3(u+1))+41-2=0
We calculate terms in parentheses: -(-3(u+1)), so:
-3(u+1)
We multiply parentheses
-3u-3
Back to the equation:
-(-3u-3)
We add all the numbers together, and all the variables
86u-(-3u-3)+39=0
We get rid of parentheses
86u+3u+3+39=0
We add all the numbers together, and all the variables
89u+42=0
We move all terms containing u to the left, all other terms to the right
89u=-42
u=-42/89
u=-42/89

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