4u+3-2(-7u-2)=3(u-1)

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Solution for 4u+3-2(-7u-2)=3(u-1) equation: 



4u+3-2(-7u-2)=3(u-1)

We move all terms to the left:

4u+3-2(-7u-2)-(3(u-1))=0

We multiply parentheses

4u+14u-(3(u-1))+4+3=0



We calculate terms in parentheses: -(3(u-1)), so:

3(u-1)

We multiply parentheses

3u-3

Back to the equation:

-(3u-3)



We add all the numbers together, and all the variables

18u-(3u-3)+7=0

We get rid of parentheses

18u-3u+3+7=0

We add all the numbers together, and all the variables

15u+10=0

We move all terms containing u to the left, all other terms to the right

15u=-10

u=-10/15

u=-2/3

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