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4t^2+56=785
We move all terms to the left:
4t^2+56-(785)=0
We add all the numbers together, and all the variables
4t^2-729=0
a = 4; b = 0; c = -729;
Δ = b2-4ac
Δ = 02-4·4·(-729)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-108}{2*4}=\frac{-108}{8} =-13+1/2 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+108}{2*4}=\frac{108}{8} =13+1/2 $
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