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4t^2+36t+81=0
a = 4; b = 36; c = +81;
Δ = b2-4ac
Δ = 362-4·4·81
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$t=\frac{-b}{2a}=\frac{-36}{8}=-4+1/2$
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