4t-2(1+t)=2(3t-1)

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Solution for 4t-2(1+t)=2(3t-1) equation: 



4t-2(1+t)=2(3t-1)

We move all terms to the left:

4t-2(1+t)-(2(3t-1))=0

We add all the numbers together, and all the variables

4t-2(t+1)-(2(3t-1))=0

We multiply parentheses

4t-2t-(2(3t-1))-2=0



We calculate terms in parentheses: -(2(3t-1)), so:

2(3t-1)

We multiply parentheses

6t-2

Back to the equation:

-(6t-2)



We add all the numbers together, and all the variables

2t-(6t-2)-2=0

We get rid of parentheses

2t-6t+2-2=0

We add all the numbers together, and all the variables

-4t=0

t=0/-4

t=0

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