4t+3/6t-7=2t+4/3t-7

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Solution for 4t+3/6t-7=2t+4/3t-7 equation:



4t+3/6t-7=2t+4/3t-7
We move all terms to the left:
4t+3/6t-7-(2t+4/3t-7)=0
Domain of the equation: 6t!=0
t!=0/6
t!=0
t∈R
Domain of the equation: 3t-7)!=0
t∈R
We get rid of parentheses
4t+3/6t-2t-4/3t+7-7=0
We calculate fractions
4t-2t+9t/18t^2+(-24t)/18t^2+7-7=0
We add all the numbers together, and all the variables
2t+9t/18t^2+(-24t)/18t^2=0
We multiply all the terms by the denominator
2t*18t^2+9t+(-24t)=0
We add all the numbers together, and all the variables
9t+2t*18t^2+(-24t)=0
Wy multiply elements
36t^3+9t+(-24t)=0
We get rid of parentheses
36t^3+9t-24t=0
We do not support etpression: t^3

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