4t+3(4-t)=2(21-t)

Solution for 4t+3(4-t)=2(21-t) equation:

4t+3(4-t)=2(21-t)

We move all terms to the left:

4t+3(4-t)-(2(21-t))=0

We add all the numbers together, and all the variables

4t+3(-1t+4)-(2(-1t+21))=0

We multiply parentheses

4t-3t-(2(-1t+21))+12=0


We calculate terms in parentheses: -(2(-1t+21)), so:

2(-1t+21)

We multiply parentheses

-2t+42

Back to the equation:

-(-2t+42)


We add all the numbers together, and all the variables

t-(-2t+42)+12=0

We get rid of parentheses

t+2t-42+12=0

We add all the numbers together, and all the variables

3t-30=0

We move all terms containing t to the left, all other terms to the right

3t=30

t=30/3

t=10