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t in (-oo:+oo)
4*sin(5*t-(pi/3)) = 0
sin(5*t-(pi/3)) = 0
sin(5*t-(pi/3)) = 0 <=> 5*t-(pi/3) = pi*k_1 i k_1 należy do I
t_1 = pi*k_1
5*t-t_1-(pi/3) = 0
5*t-t_1-(pi/3) = 0 // + -t_1-(pi/3)
5*t = -(-t_1-(pi/3)) // : 5
t = (-(-t_1-(pi/3)))/5
t = (t_1+pi/3)/5
t = (pi*k_1+pi/3)/5 i k_1 należy do I
4*sin(5*t-(pi/3)) = 0 <=> 4 = 0 or 4*sin(5*t-(pi/3)) = 0 <=> sin(5*t-(pi/3)) = 0
t = (pi*k_1+pi/3)/5
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