4r+4r-6=2(4r-3)

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Solution for 4r+4r-6=2(4r-3) equation: 



4r+4r-6=2(4r-3)

We move all terms to the left:

4r+4r-6-(2(4r-3))=0

We add all the numbers together, and all the variables

8r-(2(4r-3))-6=0



We calculate terms in parentheses: -(2(4r-3)), so:

2(4r-3)

We multiply parentheses

8r-6

Back to the equation:

-(8r-6)



We get rid of parentheses

8r-8r+6-6=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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