4p=12p(p-2)

Solution for 4p=12p(p-2) equation:

4p=12p(p-2)

We move all terms to the left:

4p-(12p(p-2))=0


We calculate terms in parentheses: -(12p(p-2)), so:

12p(p-2)

We multiply parentheses

12p^2-24p

Back to the equation:

-(12p^2-24p)


We get rid of parentheses

-12p^2+4p+24p=0

We add all the numbers together, and all the variables

-12p^2+28p=0

a = -12; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·(-12)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*-12}=\frac{-56}{-24}
=2+1/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*-12}=\frac{0}{-24}
=0
$