4p+1/5p=21

Solution for 4p+1/5p=21 equation:

4p+1/5p=21

We move all terms to the left:

4p+1/5p-(21)=0


Domain of the equation: 5p!=0

p!=0/5

p!=0

p∈R


We multiply all the terms by the denominator


4p*5p-21*5p+1=0

Wy multiply elements

20p^2-105p+1=0

a = 20; b = -105; c = +1;
Δ = b2-4ac
Δ = -1052-4·20·1
Δ = 10945
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-\sqrt{10945}}{2*20}=\frac{105-\sqrt{10945}}{40}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+\sqrt{10945}}{2*20}=\frac{105+\sqrt{10945}}{40}
$