4n=2(n+2)-12

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Solution for 4n=2(n+2)-12 equation: 



4n=2(n+2)-12

We move all terms to the left:

4n-(2(n+2)-12)=0



We calculate terms in parentheses: -(2(n+2)-12), so:

2(n+2)-12

We multiply parentheses

2n+4-12

We add all the numbers together, and all the variables

2n-8

Back to the equation:

-(2n-8)



We get rid of parentheses

4n-2n+8=0

We add all the numbers together, and all the variables

2n+8=0

We move all terms containing n to the left, all other terms to the right

2n=-8

n=-8/2

n=-4

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