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4n^2-104n+672=0
a = 4; b = -104; c = +672;
Δ = b2-4ac
Δ = -1042-4·4·672
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-8}{2*4}=\frac{96}{8} =12 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+8}{2*4}=\frac{112}{8} =14 $
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