4n2+5n-636=0

Solution for 4n2+5n-636=0 equation:

4n^2+5n-636=0

a = 4; b = 5; c = -636;
Δ = b2-4ac
Δ = 52-4·4·(-636)
Δ = 10201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10201}=101$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-101}{2*4}=\frac{-106}{8}
=-13+1/4
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+101}{2*4}=\frac{96}{8}
=12
$