# 4n2+5n-250=0

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## Solution for 4n2+5n-250=0 equation:

4n^2+5n-250=0
a = 4; b = 5; c = -250;Δ = b2-4acΔ = 52-4·4·(-250)Δ = 4025The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$The end solution:
$\sqrt{\Delta}=\sqrt{4025}=\sqrt{25*161}=\sqrt{25}*\sqrt{161}=5\sqrt{161}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{161}}{2*4}=\frac{-5-5\sqrt{161}}{8}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{161}}{2*4}=\frac{-5+5\sqrt{161}}{8}$

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