4n/6n=800n=

Solution for 4n/6n=800n= equation:

4n/6n=800n=

We move all terms to the left:

4n/6n-(800n)=0


Domain of the equation: 6n!=0

n!=0/6

n!=0

n∈R


We add all the numbers together, and all the variables

-800n+4n/6n=0

We multiply all the terms by the denominator


-800n*6n+4n=0

We add all the numbers together, and all the variables

4n-800n*6n=0

Wy multiply elements

-4800n^2+4n=0

a = -4800; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-4800)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-4800}=\frac{-8}{-9600}
=1/1200
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-4800}=\frac{0}{-9600}
=0
$