4n/3n=35n=

Solution for 4n/3n=35n= equation:

4n/3n=35n=

We move all terms to the left:

4n/3n-(35n)=0


Domain of the equation: 3n!=0

n!=0/3

n!=0

n∈R


We add all the numbers together, and all the variables

-35n+4n/3n=0

We multiply all the terms by the denominator


-35n*3n+4n=0

We add all the numbers together, and all the variables

4n-35n*3n=0

Wy multiply elements

-105n^2+4n=0

a = -105; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-105)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-105}=\frac{-8}{-210}
=4/105
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-105}=\frac{0}{-210}
=0
$