4n-2=2(2n-1)

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Solution for 4n-2=2(2n-1) equation: 



4n-2=2(2n-1)

We move all terms to the left:

4n-2-(2(2n-1))=0



We calculate terms in parentheses: -(2(2n-1)), so:

2(2n-1)

We multiply parentheses

4n-2

Back to the equation:

-(4n-2)



We get rid of parentheses

4n-4n+2-2=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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