4n-2(n-3)=2(n+3)

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Solution for 4n-2(n-3)=2(n+3) equation:



4n-2(n-3)=2(n+3)
We move all terms to the left:
4n-2(n-3)-(2(n+3))=0
We multiply parentheses
4n-2n-(2(n+3))+6=0
We calculate terms in parentheses: -(2(n+3)), so:
2(n+3)
We multiply parentheses
2n+6
Back to the equation:
-(2n+6)
We add all the numbers together, and all the variables
2n-(2n+6)+6=0
We get rid of parentheses
2n-2n-6+6=0
We add all the numbers together, and all the variables
=0
n=0/1
n=0

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