4n+5(n+3)=33

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Solution for 4n+5(n+3)=33 equation: 



4n+5(n+3)=33

We move all terms to the left:

4n+5(n+3)-(33)=0

We multiply parentheses

4n+5n+15-33=0

We add all the numbers together, and all the variables

9n-18=0

We move all terms containing n to the left, all other terms to the right

9n=18

n=18/9

n=2

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