4n+40=8(n-5)+6

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Solution for 4n+40=8(n-5)+6 equation: 



4n+40=8(n-5)+6

We move all terms to the left:

4n+40-(8(n-5)+6)=0



We calculate terms in parentheses: -(8(n-5)+6), so:

8(n-5)+6

We multiply parentheses

8n-40+6

We add all the numbers together, and all the variables

8n-34

Back to the equation:

-(8n-34)



We get rid of parentheses

4n-8n+34+40=0

We add all the numbers together, and all the variables

-4n+74=0

We move all terms containing n to the left, all other terms to the right

-4n=-74

n=-74/-4

n=18+1/2

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