4n+3(2n-5)=31

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Solution for 4n+3(2n-5)=31 equation: 



4n+3(2n-5)=31

We move all terms to the left:

4n+3(2n-5)-(31)=0

We multiply parentheses

4n+6n-15-31=0

We add all the numbers together, and all the variables

10n-46=0

We move all terms containing n to the left, all other terms to the right

10n=46

n=46/10

n=4+3/5

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