4n+2=6(1n-2)

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Solution for 4n+2=6(1n-2) equation: 



4n+2=6(1n-2)

We move all terms to the left:

4n+2-(6(1n-2))=0

We add all the numbers together, and all the variables

4n-(6(n-2))+2=0



We calculate terms in parentheses: -(6(n-2)), so:

6(n-2)

We multiply parentheses

6n-12

Back to the equation:

-(6n-12)



We get rid of parentheses

4n-6n+12+2=0

We add all the numbers together, and all the variables

-2n+14=0

We move all terms containing n to the left, all other terms to the right

-2n=-14

n=-14/-2

n=+7

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