4n+(n+2)=12(n+4)

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Solution for 4n+(n+2)=12(n+4) equation:


Simplifying
4n + (n + 2) = 12(n + 4)

Reorder the terms:
4n + (2 + n) = 12(n + 4)

Remove parenthesis around (2 + n)
4n + 2 + n = 12(n + 4)

Reorder the terms:
2 + 4n + n = 12(n + 4)

Combine like terms: 4n + n = 5n
2 + 5n = 12(n + 4)

Reorder the terms:
2 + 5n = 12(4 + n)
2 + 5n = (4 * 12 + n * 12)
2 + 5n = (48 + 12n)

Solving
2 + 5n = 48 + 12n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-12n' to each side of the equation.
2 + 5n + -12n = 48 + 12n + -12n

Combine like terms: 5n + -12n = -7n
2 + -7n = 48 + 12n + -12n

Combine like terms: 12n + -12n = 0
2 + -7n = 48 + 0
2 + -7n = 48

Add '-2' to each side of the equation.
2 + -2 + -7n = 48 + -2

Combine like terms: 2 + -2 = 0
0 + -7n = 48 + -2
-7n = 48 + -2

Combine like terms: 48 + -2 = 46
-7n = 46

Divide each side by '-7'.
n = -6.571428571

Simplifying
n = -6.571428571

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