4n*n=256

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Solution for 4n*n=256 equation:



4n*n=256
We move all terms to the left:
4n*n-(256)=0
Wy multiply elements
4n^2-256=0
a = 4; b = 0; c = -256;
Δ = b2-4ac
Δ = 02-4·4·(-256)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64}{2*4}=\frac{-64}{8} =-8 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64}{2*4}=\frac{64}{8} =8 $

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