4n(5n+5)=0

Solution for 4n(5n+5)=0 equation:

4n(5n+5)=0

We multiply parentheses

20n^2+20n=0

a = 20; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·20·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*20}=\frac{-40}{40}
=-1
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*20}=\frac{0}{40}
=0
$