4m2-8m-5=0

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Solution for 4m2-8m-5=0 equation:



4m^2-8m-5=0
a = 4; b = -8; c = -5;
Δ = b2-4ac
Δ = -82-4·4·(-5)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-12}{2*4}=\frac{-4}{8} =-1/2 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+12}{2*4}=\frac{20}{8} =2+1/2 $

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