4m-8-8m+6=2(m-3)-4(-5+m)

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Solution for 4m-8-8m+6=2(m-3)-4(-5+m) equation:



4m-8-8m+6=2(m-3)-4(-5+m)
We move all terms to the left:
4m-8-8m+6-(2(m-3)-4(-5+m))=0
We add all the numbers together, and all the variables
4m-8m-(2(m-3)-4(m-5))-8+6=0
We add all the numbers together, and all the variables
-4m-(2(m-3)-4(m-5))-2=0
We calculate terms in parentheses: -(2(m-3)-4(m-5)), so:
2(m-3)-4(m-5)
We multiply parentheses
2m-4m-6+20
We add all the numbers together, and all the variables
-2m+14
Back to the equation:
-(-2m+14)
We get rid of parentheses
-4m+2m-14-2=0
We add all the numbers together, and all the variables
-2m-16=0
We move all terms containing m to the left, all other terms to the right
-2m=16
m=16/-2
m=-8

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