4m-8+2m=3(m+4)+1

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Solution for 4m-8+2m=3(m+4)+1 equation: 



4m-8+2m=3(m+4)+1

We move all terms to the left:

4m-8+2m-(3(m+4)+1)=0

We add all the numbers together, and all the variables

6m-(3(m+4)+1)-8=0



We calculate terms in parentheses: -(3(m+4)+1), so:

3(m+4)+1

We multiply parentheses

3m+12+1

We add all the numbers together, and all the variables

3m+13

Back to the equation:

-(3m+13)



We get rid of parentheses

6m-3m-13-8=0

We add all the numbers together, and all the variables

3m-21=0

We move all terms containing m to the left, all other terms to the right

3m=21

m=21/3

m=7

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