4m-10=12+2(m+8)

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Solution for 4m-10=12+2(m+8) equation: 



4m-10=12+2(m+8)

We move all terms to the left:

4m-10-(12+2(m+8))=0



We calculate terms in parentheses: -(12+2(m+8)), so:

12+2(m+8)

determiningTheFunctionDomain
2(m+8)+12

We multiply parentheses

2m+16+12

We add all the numbers together, and all the variables

2m+28

Back to the equation:

-(2m+28)



We get rid of parentheses

4m-2m-28-10=0

We add all the numbers together, and all the variables

2m-38=0

We move all terms containing m to the left, all other terms to the right

2m=38

m=38/2

m=19

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