4m+8-6m(+2)=7

Solution for 4m+8-6m(+2)=7 equation:

4m+8-6m(+2)=7

We move all terms to the left:

4m+8-6m(+2)-(7)=0

We add all the numbers together, and all the variables

4m-6m2+8-7=0

We add all the numbers together, and all the variables

-6m^2+4m+1=0

a = -6; b = 4; c = +1;
Δ = b2-4ac
Δ = 42-4·(-6)·1
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{10}}{2*-6}=\frac{-4-2\sqrt{10}}{-12}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{10}}{2*-6}=\frac{-4+2\sqrt{10}}{-12}
$