4m+3(m-6)+20=-5m+4(3m-1)+6

Solution for 4m+3(m-6)+20=-5m+4(3m-1)+6 equation:

4m+3(m-6)+20=-5m+4(3m-1)+6

We move all terms to the left:

4m+3(m-6)+20-(-5m+4(3m-1)+6)=0

We multiply parentheses

4m+3m-(-5m+4(3m-1)+6)-18+20=0


We calculate terms in parentheses: -(-5m+4(3m-1)+6), so:

-5m+4(3m-1)+6

We multiply parentheses

-5m+12m-4+6

We add all the numbers together, and all the variables

7m+2

Back to the equation:

-(7m+2)


We add all the numbers together, and all the variables

7m-(7m+2)+2=0

We get rid of parentheses

7m-7m-2+2=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0