4m+2(m-5)=27

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Solution for 4m+2(m-5)=27 equation:



4m+2(m-5)=27
We move all terms to the left:
4m+2(m-5)-(27)=0
We multiply parentheses
4m+2m-10-27=0
We add all the numbers together, and all the variables
6m-37=0
We move all terms containing m to the left, all other terms to the right
6m=37
m=37/6
m=6+1/6

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