4ln(400/A)=3ln(200/A)

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Solution for 4ln(400/A)=3ln(200/A) equation:


D( A )

A = 0

400/A <= 0

200/A <= 0

A = 0

A = 0

400/A <= 0

400/A <= 0

400*A^-1 <= 0

400*A^-1 <= 0 // : 400

A^-1 <= 0/400

A^-1 <= 0

1/(A^1) <= 0

A <> 0

1/(A^1) <= 0 // * A^2

(A^2)/(A^1) <= 0

A^1 <= 0

A <= 0

A in (-oo:0)

200/A <= 0

200/A <= 0

200*A^-1 <= 0

200*A^-1 <= 0 // : 200

A^-1 <= 0/200

A^-1 <= 0

1/(A^1) <= 0

A <> 0

1/(A^1) <= 0 // * A^2

(A^2)/(A^1) <= 0

A^1 <= 0

A <= 0

A in (-oo:0)

A in (0:+oo)

4*ln(400/A) = 3*ln(200/A) // - 3*ln(200/A)

4*ln(400/A)-(3*ln(200/A)) = 0

4*ln(400/A)-3*ln(200/A) = 0

ln(1*(400/A)^4)-3*ln(200/A) = 0

ln((1*(400/A)^4)/((200/A)^3)) = 0

ln(((400/A)^4)/((200/A)^3)) = 0

ln(((400/A)^4)/((200/A)^3)) = ln(e^0)

((400/A)^4)/((200/A)^3) = e^0

((400/A)^4)/((200/A)^3)-e^0 = 0

3200*A^-1 = 1 // : 3200

A^-1 = 1/3200

-1 < 0

1/(A^1) = 1/3200 // * A^1

1 = 1/3200*A^1 // : 1/3200

3200 = A^1

A = 3200

A = 3200

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