4k+3(2k-6)=2-5(2k+3)

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Solution for 4k+3(2k-6)=2-5(2k+3) equation: 



4k+3(2k-6)=2-5(2k+3)

We move all terms to the left:

4k+3(2k-6)-(2-5(2k+3))=0

We multiply parentheses

4k+6k-(2-5(2k+3))-18=0



We calculate terms in parentheses: -(2-5(2k+3)), so:

2-5(2k+3)

determiningTheFunctionDomain
-5(2k+3)+2

We multiply parentheses

-10k-15+2

We add all the numbers together, and all the variables

-10k-13

Back to the equation:

-(-10k-13)



We add all the numbers together, and all the variables

10k-(-10k-13)-18=0

We get rid of parentheses

10k+10k+13-18=0

We add all the numbers together, and all the variables

20k-5=0

We move all terms containing k to the left, all other terms to the right

20k=5

k=5/20

k=1/4

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