4k(k-2)=2(k-9)

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Solution for 4k(k-2)=2(k-9) equation: 



4k(k-2)=2(k-9)

We move all terms to the left:

4k(k-2)-(2(k-9))=0

We multiply parentheses

4k^2-8k-(2(k-9))=0



We calculate terms in parentheses: -(2(k-9)), so:

2(k-9)

We multiply parentheses

2k-18

Back to the equation:

-(2k-18)



We get rid of parentheses

4k^2-8k-2k+18=0

We add all the numbers together, and all the variables

4k^2-10k+18=0

a = 4; b = -10; c = +18;
Δ = b2-4ac
Δ = -102-4·4·18
Δ = -188
Delta is less than zero, so there is no solution for the equation

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